I'm trying to write a function that either accepts a list of strings, or a single string. If it's a string, then I want to convert it to an array with just the one item so I can loop over it without fear of an error.
So how do I check if the variable is an array?
The method given in the ECMAScript standard to find the class of Object is to use the toString
method from Object.prototype
.
if(Object.prototype.toString.call(someVar) === '[object Array]') {
alert('Array!');
}
Or you could use typeof
to test if it is a string:
if(typeof someVar === 'string') {
someVar = [someVar];
}
Or if you're not concerned about performance, you could just do a concat
to a new empty Array.
someVar = [].concat(someVar);
There's also the constructor which you can query directly:
if (somevar.constructor.name == "Array") {
// do something
}
Check out a thorough treatment from T.J. Crowder's blog, as posted in his comment below.
Check out this benchmark to get an idea which method performs better: http://jsben.ch/#/QgYAV
From @Bharath, convert a string to an array using ES6 for the question asked:
const convertStringToArray = (object) => {
return (typeof object === 'string') ? Array(object) : object
}
Suppose:
let m = 'bla'
let n = ['bla','Meow']
let y = convertStringToArray(m)
let z = convertStringToArray(n)
console.log('check y: '+JSON.stringify(y)) . // check y: ['bla']
console.log('check y: '+JSON.stringify(z)) . // check y: ['bla','Meow']
user113716
In modern browsers you can do:
Array.isArray(obj)
(Supported by Chrome 5, Firefox 4.0, Internet Explorer 9, Opera 10.5 and Safari 5)
For backward compatibility you can add the following:
// Only implement if no native implementation is available
if (typeof Array.isArray === 'undefined') {
Array.isArray = function(obj) {
return Object.prototype.toString.call(obj) === '[object Array]';
}
};
If you use jQuery you can use jQuery.isArray(obj)
or $.isArray(obj)
. If you use Underscore.js you can use _.isArray(obj)
.
If you don't need to detect arrays created in different frames you can also just use instanceof
:
obj instanceof Array
Fela
I would first check if your implementation supports isArray
:
if (Array.isArray)
return Array.isArray(v);
You could also try using the instanceof
operator
v instanceof Array
ChaosPandion
jQuery also offers an $.isArray()
method:
var a = ["A", "AA", "AAA"];
if($.isArray(a)) {
alert("a is an array!");
} else {
alert("a is not an array!");
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
janr
This is the fastest among all methods (all browsers supported):
function isArray(obj){
return !!obj && obj.constructor === Array;
}
shinobi
Imagine you have this array below:
var arr = [1,2,3,4,5];
JavaScript (new and older browsers):
function isArray(arr) {
return arr.constructor.toString().indexOf("Array") > -1;
}
or
function isArray(arr) {
return arr instanceof Array;
}
or
function isArray(arr) {
return Object.prototype.toString.call(arr) === '[object Array]';
}
Then call it like this:
isArray(arr);
JavaScript (Internet Explorer 9+, Chrome 5+, Firefox 4+, Safari 5+, and Opera 10.5+)
Array.isArray(arr);
jQuery:
$.isArray(arr);
Angular:
angular.isArray(arr);
Underscore.js and Lodash:
_.isArray(arr);
Alireza
Array.isArray works fast, but it isn't supported by all versions of browsers.
So you could make an exception for others and use a universal method:
Utils = {};
Utils.isArray = ('isArray' in Array) ?
Array.isArray :
function (value) {
return Object.prototype.toString.call(value) === '[object Array]';
}
CruorVult
A simple function to check this:
function isArray(object)
{
return object.constructor === Array;
}
MidnightTortoise
There's just one line solution for this question
x instanceof Array
where x is the variable it will return true if x is an array and false if it is not.
Vikash Kumar
As MDN says in here:
use Array.isArray or Object.prototype.toString.call to differentiate
regular objects from arrays
Like this:
ajax333221
You can check the type of your variable whether it is an array with;
var myArray=[];
if(myArray instanceof Array)
{
....
}
Ahmet DAL
I would make a function to test the type of object you are dealing with...
function whatAmI(me){ return Object.prototype.toString.call(me).split(/\W/)[2]; }
// tests
console.log(
whatAmI(["aiming","@"]),
whatAmI({living:4,breathing:4}),
whatAmI(function(ing){ return ing+" to the global window" }),
whatAmI("going to do with you?")
);
// output: Array Object Function String
then you can write a simple if statement...
if(whatAmI(myVar) === "Array"){
// do array stuff
} else { // could also check `if(whatAmI(myVar) === "String")` here to be sure
// do string stuff
}
Billy Moon
I do this in a very simple way. It works for me.
Array.prototype.isArray = true;
a=[]; b={};
a.isArray // true
b.isArray // (undefined -> false)
rsbkk
This is my attempt to improve on this answer taking into account the comments:
var isArray = myArray && myArray.constructor === Array;
It gets rid of the if/else, and accounts for the possibility of the array being null or undefined
Dexygen
I have updated the jsperf fiddle with two alternative methods as well as error checking.
It turns out that the method defining a constant value in the 'Object' and 'Array' prototypes is faster than any of the other methods. It is a somewhat surprising result.
/* Initialisation */
Object.prototype.isArray = function() {
return false;
};
Array.prototype.isArray = function() {
return true;
};
Object.prototype._isArray = false;
Array.prototype._isArray = true;
var arr = ["1", "2"];
var noarr = "1";
/* Method 1 (function) */
if (arr.isArray()) document.write("arr is an array according to function<br/>");
if (!noarr.isArray()) document.write("noarr is not an array according to function<br/>");
/* Method 2 (value) - **** FASTEST ***** */
if (arr._isArray) document.write("arr is an array according to member value<br/>");
if (!noarr._isArray) document.write("noarr is not an array according to member value<br/>");
These two methods do not work if the variable takes the undefined value, but they do work if you are certain that they have a value. With regards to checking with performance in mind if a value is an array or a single value, the second method looks like a valid fast method. It is slightly faster than 'instanceof' on Chrome, twice as fast as the second best method in Internet Explorer, Opera and Safari (on my machine).
le_top
I know, that people are looking for some kind of raw JavaScript approach. But if you want think less about it, take a look at Underscore.js' isArray:
_.isArray(object)
It returns true if object is an Array.
(function(){ return _.isArray(arguments); })();
=> false
_.isArray([1,2,3]);
=> true
Eugene
You can use Array.isArray(). Here is a polyfill:
if (Array.isArray == null) {
Array.isArray = (arr) => Object.prototype.toString.call(arr) === "[object Array]"
}
Safareli
The best practice is to compare it using constructor
, something like this
if(some_variable.constructor === Array){
// do something
}
You can use other methods too, like typeOf
, converting it to a string and then comparing, but comparing it with dataType is always a better approach.
Atishay Jain
If the only two kinds of values that could be passed to this function are a string or an array of strings, keep it simple and use a typeof
check for the string possibility:
function someFunc(arg) {
var arr = (typeof arg == "string") ? [arg] : arg;
}
Tim Down
Here's my lazy approach:
if (Array.prototype.array_ === undefined) {
Array.prototype.array_ = true;
}
// ...
var test = [],
wat = {};
console.log(test.array_ === true); // true
console.log(wat.array_ === true); // false
I know it's sacrilege to "mess with" the prototype, but it appears to perform significantly better than the recommended toString
method.
Note: A pitfall of this approach is that it wont work across iframe
boundaries, but for my use case this is not an issue.
namuol
This function will turn almost anything into an array:
function arr(x) {
if(x === null || x === undefined) {
return [];
}
if(Array.isArray(x)) {
return x;
}
if(isString(x) || isNumber(x)) {
return [x];
}
if(x[Symbol.iterator] !== undefined || x.length !== undefined) {
return Array.from(x);
}
return [x];
}
function isString(x) {
return Object.prototype.toString.call(x) === "[object String]"
}
function isNumber(x) {
return Object.prototype.toString.call(x) === "[object Number]"
}
It uses some newer browser features so you may want to polyfill this for maximum support.
Examples:
> arr(null);
[]
> arr(undefined)
[]
> arr(3.14)
[ 3.14 ]
> arr(1/0)
[ Infinity ]
> gen = function*() { yield 1; yield 2; yield 3; }
[Function: gen]
> arr(gen())
[ 1, 2, 3 ]
> arr([4,5,6])
[ 4, 5, 6 ]
> arr("foo")
[ 'foo' ]
N.B. strings will be converted into an array with a single element instead of an array of chars. Delete the isString
check if you would prefer it the other way around.
I've used Array.isArray
here because it's the most robust and also simplest.
mpen
The following could be used if you know that your object doesn't have a concat method.
var arr = [];
if (typeof arr.concat === 'function') {
console.log("It's an array");
}
yesil
var a = [], b = {};
console.log(a.constructor.name == "Array");
console.log(b.constructor.name == "Object");
Alauddin Afif Cassandra
The best solution I've seen is a cross-browser replacement for typeof. Check Angus Croll's solution.
The TL;DR version is below, but the article is a great discussion of the issue so you should read it if you have time.
Object.toType = function(obj) {
return ({}).toString.call(obj).match(/\s([a-z|A-Z]+)/)[1].toLowerCase();
}
// ... and usage:
Object.toType([1,2,3]); //"array" (all browsers)
// or to test...
var shouldBeAnArray = [1,2,3];
if(Object.toType(shouldBeAnArray) === 'array'){/* do stuff */};
John Wundes
There is a nice example in Stoyan Stefanov's book JavaScript Patterns which is supposed to handle all possible problems as well as use the ECMAScript 5 method Array.isArray().
So here it is:
if (typeof Array.isArray === "undefined") {
Array.isArray = function (arg) {
return Object.prototype.toString.call(arg) === "[object Array]";
};
}
By the way, if you are using jQuery, you can use its method $.isArray().
Salvador Dali
You could use the isArray method, but I would prefer to check with:
Object.getPrototypeOf(yourvariable) === Array.prototype
STEEL
function isArray(value) {
if (value) {
if (typeof value === 'object') {
return (Object.prototype.toString.call(value) == '[object Array]')
}
}
return false;
}
var ar = ["ff","tt"]
alert(isArray(ar))
RoboTamer
A simple function for testing if an input value is an array is the following:
function isArray(value)
{
return Object.prototype.toString.call(value) === '[object Array]';
}
This works cross browser, and with older browsers. This is pulled from T.J. Crowders' blog post
Brad Parks
You can try this:
var arr = []; (or) arr = new Array();
var obj = {}; (or) arr = new Object();
arr.constructor.prototype.hasOwnProperty('push') //true
obj.constructor.prototype.hasOwnProperty('push') // false
VIJAY P
In your case you may use concat
method of Array which can accept single objects as well as array (and even combined):
function myFunc(stringOrArray)
{
var arr = [].concat(stringOrArray);
console.log(arr);
arr.forEach(function(item, i)
{
console.log(i, "=", item);
})
}
myFunc("one string");
myFunc(["one string", "second", "third"]);
concat
seems to be one of the oldest methods of Array (even IE 5.5 knows it well).
kolyasegRetrieved from : http:www.stackoverflow.com/questions/4775722/how-can-i-check-if-an-object-is-an-array