I would like to grep
for a string, but also show the preceding five lines and the following five lines as well as the matched line. How would I be able to do this?
For BSD or GNU grep
you can use -B num
to set how many lines before the match and -A num
for the number of lines after the match.
grep -B 3 -A 2 foo README.txt
If you want the same number of lines before and after you can use -C num
.
grep -C 3 foo README.txt
This will show 3 lines before and 3 lines after.
Pat Notz
-A
and -B
will work, as will -C n
(for n
lines of context), or just -n
(for n
lines of context... as long as n is 1 to 9).
Stu
ack works with similar arguments as grep, and accepts -C
. But it's usually better for searching through code.
elmarco
grep astring myfile -A 5 -B 5
That will grep "myfile" for "astring", and show 5 lines before and after each match
dbr
I normally use
grep searchstring file -C n # n for number of lines of context up and down
Many of the tools like grep also have really great man files too. I find myself referring to grep's man page a lot because there is so much you can do with it.
man grep
Many GNU tools also have an info page that may have more useful information in addition to the man page.
info grep
Sam Merrell
Use grep
$ grep --help | grep -i context
Context control:
-B, --before-context=NUM print NUM lines of leading context
-A, --after-context=NUM print NUM lines of trailing context
-C, --context=NUM print NUM lines of output context
-NUM same as --context=NUM
Chiel ten Brinke
ripgrep
If you care about the performance, use ripgrep
which has similar syntax to grep
, e.g.
rg -C5 "pattern" .
-C
,--context NUM
- Show NUM lines before and after each match.
There are also parameters such as -A
/--after-context
and -B
/--before-context
.
The tool is built on top of Rust's regex engine which makes it very efficient on the large data.
kenorb
Search for "17655" in /some/file.txt
showing 10 lines context before and after (using Awk
), output preceded with line number followed by a colon. Use this on Solaris when grep
does not support the -[ACB]
options.
awk '
/17655/ {
for (i = (b + 1) % 10; i != b; i = (i + 1) % 10) {
print before[i]
}
print (NR ":" ($0))
a = 10
}
a-- > 0 {
print (NR ":" ($0))
}
{
before[b] = (NR ":" ($0))
b = (b + 1) % 10
}' /some/file.txt;
Malcolm Boekhoff
Here is the @Ygor solution in awk
awk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r[(NR-c+1)%b];print;c=a}b{r[NR%b]=$0}' b=3 a=3 s="pattern" myfile
Note: Replace a
and b
variables with number of lines before and after.
It's especially useful for system which doesn't support grep's -A
, -B
and -C
parameters.
kenorb
$ grep thestring thefile -5
-5
gets you 5
lines above and below the match 'thestring' is equivalent to -C 5
or -A 5 -B 5
.
JBone
Grep has an option called Context Line Control
, you can use the --context
in that, simply,
| grep -C 5
or
| grep -5
Should do the trick
prime
If you search code often, AG the silver searcher is much more efficient (ie faster) than grep.
You show context lines by using -C option.
Eg:
ag -C 3 "foo" myFile
line 1
line 2
line 3
line that has "foo"
line 5
line 6
line 7
Rose
I do it the compact way:
grep -5 string file
That is the equivalent of:
grep -A 5 -B 5 string file
franzisk
You can use option -A
(after) and -B
(before) in your grep command.
Try grep -nri -A 5 -B 5 .
Issam.Chorfa
Retrieved from : http:www.stackoverflow.com/questions/9081/grep-a-file-but-show-several-surrounding-lines
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